CONTOH PENILAIAN

PEDOMAN PENSKORAN
BOBOT SOAL :
1) B – S = 1
2) PILIHAN GANDA = 2
3) MENJODOHKAN = 2
4) ISIAN SINGKAT = 3
5) ESSAY = 4

RUMUS PENSKORAN :

1. Pilihan ganda

SM = ( R - W ) X WT
N - 1

2. Isian / Menjodohkan / B - S

S = R X WT

3. ESSAY

S = R X WT


4. TS = 50 + ( X - M ) X 10
SD

5. Nilai Akhir = TS + 20

CONTOH PERHITUNGAN
 Banyak Soal :
a. PG = 10 soal
b. Isian = 15 soal
c. Essay = 5 soal
 Seorang peserta didik mendapat kebenaran.
PG = 8 soal
Isian = 11 soal
Essay = 3 soal




 Selanjutnya mencari
SM 1 = Total Skore

PG = 10 soal, 10 x 2 = 20
Isian = 15 soal, 15 x 3 = 45
Essay = 5 soal, 5 x 5 = 25 +
90
M = Medium ( Titik tengah )
M = ½ SM 1, jadi M = ½ x 90 = 45

Lalu cari SD ( Standar Deviasi ) = 1/3 x SM 1
SD = 1/3 x 45 = 15
 Masukkan rumus penskoran

 Pilihan ganda

SM = ( R - W ) X WT
N - 1

SM = ( 8 - 2 ) X 2
10-2

SM = 7 ¾ x 2 = 15 ½

 Isian

S = R X WT

S = 11 X 3 = 33

 ESSAY

S = R X WT

S = 3 X 5 = 15

Jadi SM peserta didik = 15 ½ + 33 + 15 = 63 ½









 TS = 50 + ( X - M ) X 10
SD

TS = 50 + ( 63 ½ - 45 ) X 10
15

TS = 50 + 1,23 X 10

TS = 50 + 12,3 = 62,3

 Nilai Akhir = TS + 20

Nilai Akhir = 62,3 + 20 = 82,3

Jadi peserta didik tadi memperoleh nilai 82,3


Pendekatan terdekat dan cepat :
 Banyak Soal :
• PG = 10 soal
• Isian = 15 soal
• Essay = 5 soal
 Seorang peserta didik mendapat kebenaran.
• PG = 8 soal, 8 x 2 = 16
• Isian = 11 soal, 11 x 3 = 33
• Essay = 3 soal, 3 x 5 = 15 +
64
 Selanjutnya mencari
PG = 10 soal, 10 x 2 = 20
Isian = 15 soal, 15 x 3 = 45
Essay = 5 soal, 5 x 5 = 25 +
90

Lalu 64 x 10 = 71,1 selanjutnya tambah 10 menjadi 81,1
90
Cukup mendekati hasilnya !!!

Selamat Mencoba !!!!